i am currently using leancloud developer mode, actually i am using different android devices to create user accounts but whenever a new account is created the latest user account automatically login to all the other devices.is there any reason as to why this occurs and any solution will be accepted.
20年3月18日
20年3月20日
Can you provide more details?
Users will not log in unless the client side (application) invoke login APIs with related account information such as username, password, verification code, etc.
1.Register Activity: Also launches an intent to specific activities according to user status. But when a new account is created on a different device all the devices logs in to the latest account created.
if(NetworkConnection.isConnectedToInternet(getApplicationContext())){
switch(v.getId()){
case R.id.cancel:
this.finishAffinity();
break;
case R.id.Re:
String name = edit_rename.getText().toString().trim();
String email = edit_reemail.getText().toString().trim();
String password = edit_repwd.getText().toString().trim();
if(TextUtils.isEmpty(name)){
Toast.makeText(RegisterActivity.this,"Please enter username",Toast.LENGTH_SHORT).show();
break;
}
if(TextUtils.isEmpty(email)){
Toast.makeText(RegisterActivity.this,"Please enter email",Toast.LENGTH_SHORT).show();
break;
}
if(TextUtils.isEmpty(password)){
Toast.makeText(RegisterActivity.this,"Please enter password",Toast.LENGTH_SHORT).show();
break;
}
if(rbGrp.getCheckedRadioButtonId() == -1){
Toast.makeText(RegisterActivity.this,"Please Select Status",Toast.LENGTH_SHORT).show();
break;
}
if(edit_rename.getText().toString().trim().length() != 0 && edit_reemail.getText().toString().trim().length() != 0&&
edit_repwd.getText().toString().trim().length() != 0 && rb1.isChecked() || rb2.isChecked() || rb3.isChecked()){
AVUser user= new AVUser();
user.setUsername(name);
user.setEmail(email);
user.setPassword(password);
if(rb1.isChecked()){
user.put("Status","Administrator");
}else if(rb2.isChecked()){
user.put("Status","Lecturer");
}else {
user.put("Status","Student");
}
user.signUpInBackground(new SignUpCallback() {
@Override
public void done(AVException e) {
if(e==null){
if(rb1.isChecked()){
// clientId 为 Tom
AVIMClient avimClient = AVIMClient.getInstance(edit_rename.getText().toString());
avimClient.open(new AVIMClientCallback() {
@Override
public void done(AVIMClient avimClient, AVIMException e) {
Intent i = new Intent(RegisterActivity.this,MainActivity.class);
i.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP | Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(i);
finish();
}
});
}else if(rb2.isChecked()){
// clientId 为 Tom
AVIMClient avimClient = AVIMClient.getInstance(edit_rename.getText().toString());
avimClient.open(new AVIMClientCallback() {
@Override
public void done(AVIMClient client, AVIMException e) {
Intent i = new Intent(RegisterActivity.this,LecturerMainActivity.class);
i.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP | Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(i);
finish();
}
});
}else {
// clientId 为 Tom
AVIMClient avimClient = AVIMClient.getInstance(edit_rename.getText().toString());
avimClient.open(new AVIMClientCallback() {
@Override
public void done(AVIMClient client, AVIMException e) {
Intent i = new Intent(RegisterActivity.this,StudentMainActivity.class);
i.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP | Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(i);
finish();
}
});
}
}
else{
Toast.makeText(RegisterActivity.this,"账号已经存在，请重新输入",Toast.LENGTH_SHORT).show();
}
}
});
}
break;
case R.id.to_logpg_txt:
Intent intent2=new Intent(this,LogInActivity.class);
startActivity(intent2);
break;
default:break;
}
}else
Toast.makeText(RegisterActivity.this,"No Connection Available",Toast.LENGTH_SHORT).show();
}2.Log In: this is code for logging in as i am accessing different activities due to the status of the user
if(NetworkConnection.isConnectedToInternet(getApplicationContext())){
switch (v.getId()){
case R.id.login:
String name_email=edit_name.getText().toString().trim();
String password=edit_pwd.getText().toString().trim();
if(TextUtils.isEmpty(name_email)){
Toast.makeText(LogInActivity.this,"Please enter username",Toast.LENGTH_SHORT).show();
break;
}
if(TextUtils.isEmpty(password)){
Toast.makeText(LogInActivity.this,"Please enter password",Toast.LENGTH_SHORT).show();
break;
}
if(!TextUtils.isEmpty(name_email) && !TextUtils.isEmpty(password)){
AVUser.logInInBackground(name_email, password, new LogInCallback<AVUser>() {
@Override
public void done(AVUser avUser, AVException e) {
if(e==null){
AVQuery<AVObject> user_status_query = new AVQuery<>("_User");
user_status_query.findInBackground(new FindCallback<AVObject>() {
@Override
public void done(List<AVObject> list, AVException e) {
for(AVObject avObject:list){
String status_n= (String) avObject.get("Status");
if(status_n.equals("Administrator")){
// 与服务器连接
Intent i = new Intent(LogInActivity.this,MainActivity.class);
i.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP | Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(i);
finish();
}
else if(status_n.equals("Lecturer")){
Intent i = new Intent(LogInActivity.this,LecturerMainActivity.class);
i.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP | Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(i);
finish();
}else if(status_n.equals("Student")){
Intent i = new Intent(LogInActivity.this,StudentMainActivity.class);
i.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP | Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(i);
finish();
}
}
}
});
// 执行其他逻辑
}
else{
Toast.makeText(LogInActivity.this,"用户名或密码错误",Toast.LENGTH_SHORT).show();
}
}
});
}
break;
case R.id.register:
Intent intent=new Intent(this,RegisterActivity.class);
startActivity(intent);
break;
case R.id.forget:
break;
}
}else
Toast.makeText(LogInActivity.this,"No Connection Available",Toast.LENGTH_SHORT).show();
}According to the code sample you posted, it seems that users cannot log in unless they fill in their email and password, thus no automatic log in.
But this user query seems incomplete:
AVQuery<AVObject> user_status_query = new AVQuery<>("_User");
user_status_query.findInBackground(new FindCallback<AVObject>() ...It seems that you forget to specify the query condition?
Related documentation: